WebThe sum of the first n terms of an AP is (3n^2+6n). Find the nth term and the 15th term of this AP.CLASS-10PROGRESSIONS CBSETELANGANA AND ANDHRA PRADESH STAT... WebThe sum of first n terms of A.P. is 3n+n 2 then Find second, third and 15 th term. This question has multiple correct options A 6 B 8 C 32 D 45 Medium Solution Verified by Toppr Correct options are A) , B) and C) Here S n=3n+n 2 Now, first term a=S 1⇒a=3×1+1 2=4 and Sum of first two terms= a 1+a 2=a+(a+d)=S 2=3×2+2 2=10 ⇒2a+d=10⇒8+d=10⇒d=2
The sum of the first n terms of an AP is given by Sn = (3n^2
WebIf t5 and t12 of an AP are 14 and 35 respectively, find the first 5 terms of the AP. a) 2, 3, 9, 11, 14. b) 2, 4, 8, 12, 14. c) 2, 5, 8, 11, 14 ... 3n2 + 3o2 – p. 2 = 0. ii. m – 2o + q = 0. a. (i) is correct. b. (ii) is correct ... Both are correct. d. None are correct. 16.Find the sum of n terms of the series 1.2 + 3.22 + 5.23 + 7.24 ... WebMar 22, 2024 · (1) Putting n = 2 in (1) S2 = 3 × 22 + 5 × 2 = 3 × 4 + 5 × 2 = 12 + 10 = 22 Sum of first two terms = First term + Second term S2 = a1 + a2 S2 – a1 = a2 a2 = S2 – a1 Putting a1 = 8 , S2 = 22 a2 = 22 – 8 = 14 Thus, a1 = 8 , a2 = 14 Common difference (d) = Second term – First term = a2 – a1 = 14 – 8 = 6 Now we have a = ... razor sharp zero friction blade
The sum of the first n terms of an AP is (3n^2+6n). Find the nth …
WebApr 15, 2024 · The sum of the first n terms of an AP is given by Sn = (3n2 – n). Find its (i) nth term, (ii) first term and (iii) common difference. arithmetic progression class-10 1 Answer +1 vote answered Apr 15, 2024 by Nidhi01 (60.1k points) selected Apr 16, 2024 by Vevek01 Best answer Sn = 3n2 – n S1 = 3 (1)2 – 1 = 3 – 1 = 2 S2 = 3 (2)2 – 2 = 12 – 2 = 10 WebAug 28, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. Advertisement Expert-Verified Answer 1282 people found it helpful Brainly User Let the … WebOct 13, 2024 · If the sum of first n terms of an A.P. is given by Sn= 3n2+5n, find the nth term of the A.P. Advertisement Loved by our community 48 people found it helpful janhavijadhav2910 Sn=3n²+5n S₁=3 (1)²+5 (1) =3+5 =8............= a S₂=3 (2)²+5 (2) =12+10 =22 so on subtracting S₂-S₁=A₂ 22-8 =14 So∴ a=8 d=A₂-A₁ =14-8 =6 So nth term is An=a+ (n-1)d … razor shave dry venus on the go